5m^2+22m=15

Solution for 5m^2+22m=15 equation:

5m^2+22m=15

We move all terms to the left:

5m^2+22m-(15)=0

a = 5; b = 22; c = -15;
Δ = b2-4ac
Δ = 222-4·5·(-15)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-28}{2*5}=\frac{-50}{10}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+28}{2*5}=\frac{6}{10}
=3/5
$